Is hydraulic hose too strong?

The conventional method of hydraulic hose construction may be overly conservative. If so, perhaps hose could be lighter, thinner, and more flexible without compromising strength or service life.

What is in this article?:

Response to hydrostatic pressure

First, we’ll examine the horizontal force created by the fluid pressure. The magnitude is calculated the same as before, but with one difference. The important diameter is not the braid mean diameter, Dm, but, rather, the end fitting nipple’s outside diameter, Dn. The horizontal force is developed from the pressure acting directly on the nipple; the braid must support the horizontal force (and the vertical force).

Figure 2. The pressure force, H, does not act directly at Dm, as indicated in Figure 1, but, rather, on the nipple OD. Figure 3. The pressure force, V, does not act directly at Dm, as indicated in Figure 1, but, rather, on hose’s ID.

The horizontal pressure force, H, always pushes directly against the fitting’s nipple. If the reinforcement wasn’t secured to the connector’s shell or socket, the pressure would push the nipple out of the hose. The horizontal force’s magnitude is the same, regardless of tube’s wall thickness does.

This is where the calculation of the reinforcement requirement changes from that suggested by the Evans model. The magnitude of the reaction force carried by the reinforcement diameter does not change even if the tube wall thickness does. The reaction force is related to the nipple’s outside diameter, and it is carried by the reinforcement!

Now let’s look at the vertical force, V, created by the fluid pressure. Similar to the Evans analysis, we show the vertical force acting at the inside diameter of the tube; it does not act directly on the reinforcement. The reinforcement provides the reaction force to the pressure driven forces applied to the inner surface of the tube.

Justification
The mechanics to justify moving the vertical (radial) force, V, to the inside diameter of the tube is two fold. First, the tube is trapped between the fluid and the reinforcement. The fluid pushes radially outward, and the reinforcement pushes back with equal force. Second, the lay of the reinforcement moves to the neutral angle.

The Evans solution for the direction of the neutral angle as 54° 44´ has been verified by decades of experience. Experience also tells us that the braid will move toward the neutral angle unless it is somehow blocked.

This is because if the horizontal force is greater than the vertical force, the hose reinforcement will elongate until the horizontal and vertical forces are equal. That only happens when the reinforcement braid angle is 54° 44´. The reverse is also true: if the horizontal force is less than the vertical force, the hose reinforcement will shrink until it reaches the neutral angle. This is why hose swells and shortens when pressurized.

To explain, we know from experience that when under pressure, the reinforcement always aligns at the neutral angle. So where does the vertical force act? It must be adjacent to the horizontal force so that the resulting force created by the vector sum of the horizontal and vertical forces lies at the neutral angle.

A suggested improvement
My suggestion is for hose manufacturers to change from using the mean diameter of the reinforcement, Dm, to the connector’s nipple diameter, Dn. Any geometric change to the tube or braid thickness has no impact on the magnitude of the force the reinforcement must support.

In summary, the hydrostatic forces, H and V, act on the inner surface of the tube; that is, at the nipple diameter and along the related wetted pitch inside tube. The resultant force acts along the neutral angle and the magnitude of the resultant force is:

FR = P × 1.36 × Dn2.

Following Evans’ analysis, we can conclude that:

R × N = P × 1.36 × Dn2.

We now have created a model in which we know that the optimum design strength of the reinforcement must be equal to the connector’s nipple diameter instead of the mean diameter of the reinforcement. This means the Evans approach is too conservative for OEMs and users that want a lighter weight, yet equally strong and reliable hose assembly that is designed using the lower forces based on the nipple OD. Adopting this suggested approach may lead to the next generation hose design.

Design theory for optimization
We calculate the hydrostatic force based on the nipple’s diameter, which reduces the hose reinforcement design to N × R. We know the braid angle, so the designer simply selects the solution for N × R.

The minimum number of reinforcement ends, N, must provide sufficient coverage of the outer surface of the hose tube to prevent it from extruding between the reinforcement strands. Furthermore, the product of N and R must exceed the minimum burst pressure. This means that the geometric solution for N × R may require two or more layers of reinforcement to keep the hose tube from failing.

Conclusions
The Evans analysis is successful because it is conservative. It is based on using the mean reinforcement (braid or spiral) diameter as the boundary for generating the hydrostatic force. However, the free-body-diagram at the wetted surfaces indicates the horizontal force is generated by the pressure acting directly on the nipple. The result is that the magnitude of the horizontal and vertical forces is reduced from that calculated by using the mean reinforcement diameter. These reductions will allow manufacturers to design hose that may be lighter and more flexible than hose currently based on the Evans analysis model.

Peter Stroempl is retired after working 33 years in the hydraulics industry.

 

Discuss this Article 4

Anonymous (not verified)
on Nov 12, 2012

How well or poorly does Mr. Stroempl's proposal agree with physical testing?

Pete Stroempl (not verified)
on Nov 21, 2012

Dear Anonymous: Thank you for the question. The physical testing is left to the hose engineers. My article is proposed to correct a mistaken notion presented in the Evan's book. The article proposes to the hose engineer that the axial force is generated at the nipple and is reacted to by the reinforcement. It is proposed the "action" is not at mean reinforcement diameter but at the nipple diameter. The proposed analysis of the internal forces offers justification for constructing lighter and smaller diameter hose assemblies that safely meet the technical requirements. Thanks again. pjs

Alan Hitchcox
on Dec 12, 2012

We also have comments about this article in our Hydraulics & Pneumatics LinkedIn group.
Here is a link:
http://www.linkedin.com/groups/Retired-engineer-poses-question-is-40236....

Anonymous (not verified)
on Mar 12, 2013

I do not think that this approach is viable- at least if there is a consistent neutral angle, as the author acknowledges is well known and has been verified with experimentation.

Here's my rational:
In the derrivation of end and hoop forces above substitute the true internal diameter (let's call it D_I). Now it stands to reason that the braid angle will continue to be related to the diameter of the reinforcement, D_M. Substituting these values and rederiving the neutral angle would give Theta = inverse tangent of 2*D_M/D_I. This would mean that the neutral angle would vary with tube wall and reinforcement thickness- if this theory is true.

The other factor which is problematic about this assumption in general is the idea that burst pressure is the primary factor which is limiting the performance capacity of hoses.

Food for thought.... YES!
Answer to reduce cost from hose designs.... NO! (IMO)

Post new comment
Sign In or register to use your Hydraulics & Pneumatics ID
(optional)
New blog posts

Subscribe to the Hydraulics & Pneumatics Newsletter!

Keep up with the latest news with our newsletter

Hydraulics & Pneumatics Bookstore

Our online bookstore features most of the industry’s most popular and classic technical training books available.  

Click below to browse the bookshelves today!

Follow Us